Mary spent
310 of her money on 10 croissants and 8 biscuits. If each croissant costs four times as much as a biscuit, how many croissants could Mary buy with the rest of her money?
| |
Croissants |
Biscuits |
| Number |
10 |
8 |
| Value |
4 u |
1 u |
| Total value |
40 u |
8 u |
Cost of 1 biscuit = 1 u
Cost of 1 croissant = 4 u
Total cost of 10 croissants and 8 biscuits
= 10 x 4 u + 8 x 1 u
= 48 u
Fraction of Mary's money left
= 1 -
310 =
710310 of Mary's money = 48 u
110 of Mary's money = 48 u ÷ 3 = 16 u
710 of Mary's money = 16 u x 7 = 112 u
Number of croissants that Mary could buy
= 112 u ÷ 4 u
= 28
Answer(s): 28
