Linda spent
211 of her money on 5 croissants and 4 wafers. If each croissant costs four times as much as a wafer, how many wafers could Linda buy with the rest of her money?
| |
Croissants |
Wafers |
| Number |
5 |
4 |
| Value |
4 u |
1 u |
| Total value |
20 u |
4 u |
Cost of 1 wafer = 1 u
Cost of 1 croissant = 4 u
Total cost of 5 croissants and 4 wafers
= 5 x 4 u + 4 x 1 u
= 24 u
Fraction of Linda's money left
= 1 -
211 =
911211 of Linda's money = 24 u
111 of Linda's money = 24 u ÷ 2 = 12 u
911 of Linda's money = 12 u x 9 = 108 u
Number of wafers that Linda could buy
= 108 u ÷ 1 u
= 108
Answer(s): 108
