Abi spent
38 of her money on 10 wafers and 7 shortbreads. If each wafer costs twice as much as a shortbread, how many shortbreads could Abi buy with the rest of her money?
| |
Wafers |
Shortbreads |
| Number |
10 |
7 |
| Value |
2 u |
1 u |
| Total value |
20 u |
7 u |
Cost of 1 shortbread = 1 u
Cost of 1 wafer = 2 u
Total cost of 10 wafers and 7 shortbreads
= 10 x 2 u + 7 x 1 u
= 27 u
Fraction of Abi's money left
= 1 -
38 =
5838 of Abi's money = 27 u
18 of Abi's money = 27 u ÷ 3 = 9 u
58 of Abi's money = 9 u x 5 = 45 u
Number of shortbreads that Abi could buy
= 45 u ÷ 1 u
= 45
Answer(s): 45
