Hazel spent
811 of her money on 3 macarons and 10 cupcakes. If each macaron costs twice as much as a cupcake, how many macarons could Hazel buy with the rest of her money?
| |
Macarons |
Cupcakes |
| Number |
3 |
10 |
| Value |
2 u |
1 u |
| Total value |
6 u |
10 u |
Cost of 1 cupcake = 1 u
Cost of 1 macaron = 2 u
Total cost of 3 macarons and 10 cupcakes
= 3 x 2 u + 10 x 1 u
= 16 u
Fraction of Hazel's money left
= 1 -
811 =
311811 of Hazel's money = 16 u
111 of Hazel's money = 16 u ÷ 8 = 2 u
311 of Hazel's money = 2 u x 3 = 6 u
Number of macarons that Hazel could buy
= 6 u ÷ 2 u
= 3
Answer(s): 3
