Roshel spent
38 of her money on 4 wafers and 7 biscuits. If each wafer costs five times as much as a biscuit, how many wafers could Roshel buy with the rest of her money?
| |
Wafers |
Biscuits |
| Number |
4 |
7 |
| Value |
5 u |
1 u |
| Total value |
20 u |
7 u |
Cost of 1 biscuit = 1 u
Cost of 1 wafer = 5 u
Total cost of 4 wafers and 7 biscuits
= 4 x 5 u + 7 x 1 u
= 27 u
Fraction of Roshel's money left
= 1 -
38 =
5838 of Roshel's money = 27 u
18 of Roshel's money = 27 u ÷ 3 = 9 u
58 of Roshel's money = 9 u x 5 = 45 u
Number of wafers that Roshel could buy
= 45 u ÷ 5 u
= 9
Answer(s): 9
