Kimberly spent
35 of her money on 6 tarts and 3 wafers. If each tart costs thrice as much as a wafer, how many wafers could Kimberly buy with the rest of her money?
| |
Tarts |
Wafers |
| Number |
6 |
3 |
| Value |
3 u |
1 u |
| Total value |
18 u |
3 u |
Cost of 1 wafer = 1 u
Cost of 1 tart = 3 u
Total cost of 6 tarts and 3 wafers
= 6 x 3 u + 3 x 1 u
= 21 u
Fraction of Kimberly's money left
= 1 -
35 =
2535 of Kimberly's money = 21 u
15 of Kimberly's money = 21 u ÷ 3 = 7 u
25 of Kimberly's money = 7 u x 2 = 14 u
Number of wafers that Kimberly could buy
= 14 u ÷ 1 u
= 14
Answer(s): 14
