Dana spent
25 of her money on 6 croissants and 8 muffins. If each croissant costs four times as much as a muffin, how many croissants could Dana buy with the rest of her money?
| |
Croissants |
Muffins |
| Number |
6 |
8 |
| Value |
4 u |
1 u |
| Total value |
24 u |
8 u |
Cost of 1 muffin = 1 u
Cost of 1 croissant = 4 u
Total cost of 6 croissants and 8 muffins
= 6 x 4 u + 8 x 1 u
= 32 u
Fraction of Dana's money left
= 1 -
25 =
3525 of Dana's money = 32 u
15 of Dana's money = 32 u ÷ 2 = 16 u
35 of Dana's money = 16 u x 3 = 48 u
Number of croissants that Dana could buy
= 48 u ÷ 4 u
= 12
Answer(s): 12
