The figure, not drawn to scale, is made up of Rectangle E and Rectangle F overlapping each other. The area of Rectangle E is
34 the area of Rectangle F. Given that
16 of Rectangle E is shaded. What fraction of the total area of the figure is unshaded?
Rectangle E |
Rectangle F |
3x2 = 6 u |
4x2 = 8 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
5x1 |
1x1 |
|
1 u |
5 u |
1 u |
7 u |
Rectangle E and Rectangle F share the same shaded area.
Rectangle E is the combined repeated identity. Make the area of Rectangle E the same. LCM of 3 and 6 is 6.
Total unshaded areas
= 5 u + 7 u
= 12 u
Total area of the figure
= 1 u + 5 u + 7 u
= 13 u
Fraction of the figure unshaded
=
1213 Answer(s):
1213