The figure, not drawn to scale, is made up of Rectangle H and Rectangle J overlapping each other. The area of Rectangle H is
15 the area of Rectangle J. Given that
14 of Rectangle H is shaded. What fraction of the total area of the figure is unshaded?
Rectangle H |
Rectangle J |
1x4 = 4 u |
5x4 = 20 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
3x1 |
1x1 |
|
1 u |
3 u |
1 u |
19 u |
Rectangle H and Rectangle J share the same shaded area.
Rectangle H is the combined repeated identity. Make the area of Rectangle H the same. LCM of 1 and 4 is 4.
Total unshaded areas
= 3 u + 19 u
= 22 u
Total area of the figure
= 1 u + 3 u + 19 u
= 23 u
Fraction of the figure unshaded
=
2223 Answer(s):
2223