The figure, not drawn to scale, is made up of Rectangle R and Rectangle S overlapping each other. The area of Rectangle R is
57 the area of Rectangle S. Given that
15 of Rectangle R is shaded. What fraction of the total area of the figure is unshaded?
Rectangle R |
Rectangle S |
5x1 = 5 u |
7x1 = 7 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
4x1 |
1x1 |
|
1 u |
4 u |
1 u |
6 u |
Rectangle R and Rectangle S share the same shaded area.
Rectangle R is the combined repeated identity. Make the area of Rectangle R the same. LCM of 5 and 5 is 5.
Total unshaded areas
= 4 u + 6 u
= 10 u
Total area of the figure
= 1 u + 4 u + 6 u
= 11 u
Fraction of the figure unshaded
=
1011 Answer(s):
1011