The figure, not drawn to scale, is made up of Rectangle D and Rectangle E overlapping each other. The area of Rectangle D is
14 the area of Rectangle E. Given that
13 of Rectangle D is shaded. What fraction of the total area of the figure is unshaded?
| Rectangle D |
Rectangle E |
| 1x3 = 3 u |
4x3 = 12 u |
| Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
| 1x1 |
2x1 |
1x1 |
|
| 1 u |
2 u |
1 u |
11 u |
Rectangle D and Rectangle E share the same shaded area.
Rectangle D is the combined repeated identity. Make the area of Rectangle D the same. LCM of 1 and 3 is 3.
Total unshaded areas
= 2 u + 11 u
= 13 u
Total area of the figure
= 1 u + 2 u + 11 u
= 14 u
Fraction of the figure unshaded
=
1314 Answer(s):
1314 
