The figure, not drawn to scale, is made up of Rectangle S and Rectangle T overlapping each other. The area of Rectangle S is
12 the area of Rectangle T. Given that
14 of Rectangle S is shaded. What fraction of the total area of the figure is unshaded?
Rectangle S |
Rectangle T |
1x4 = 4 u |
2x4 = 8 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
3x1 |
1x1 |
|
1 u |
3 u |
1 u |
7 u |
Rectangle S and Rectangle T share the same shaded area.
Rectangle S is the combined repeated identity. Make the area of Rectangle S the same. LCM of 1 and 4 is 4.
Total unshaded areas
= 3 u + 7 u
= 10 u
Total area of the figure
= 1 u + 3 u + 7 u
= 11 u
Fraction of the figure unshaded
=
1011 Answer(s):
1011