The figure, not drawn to scale, is made up of Rectangle D and Rectangle E overlapping each other. The area of Rectangle D is
14 the area of Rectangle E. Given that
16 of Rectangle D is shaded. What fraction of the total area of the figure is unshaded?
Rectangle D |
Rectangle E |
1x6 = 6 u |
4x6 = 24 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
5x1 |
1x1 |
|
1 u |
5 u |
1 u |
23 u |
Rectangle D and Rectangle E share the same shaded area.
Rectangle D is the combined repeated identity. Make the area of Rectangle D the same. LCM of 1 and 6 is 6.
Total unshaded areas
= 5 u + 23 u
= 28 u
Total area of the figure
= 1 u + 5 u + 23 u
= 29 u
Fraction of the figure unshaded
=
2829 Answer(s):
2829