The figure, not drawn to scale, is made up of Rectangle C and Rectangle D overlapping each other. The area of Rectangle C is
14 the area of Rectangle D. Given that
14 of Rectangle C is shaded. What fraction of the total area of the figure is unshaded?
| Rectangle C |
Rectangle D |
| 1x4 = 4 u |
4x4 = 16 u |
| Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
| 1x1 |
3x1 |
1x1 |
|
| 1 u |
3 u |
1 u |
15 u |
Rectangle C and Rectangle D share the same shaded area.
Rectangle C is the combined repeated identity. Make the area of Rectangle C the same. LCM of 1 and 4 is 4.
Total unshaded areas
= 3 u + 15 u
= 18 u
Total area of the figure
= 1 u + 3 u + 15 u
= 19 u
Fraction of the figure unshaded
=
1819 Answer(s):
1819 
