The figure, not drawn to scale, is made up of Rectangle H and Rectangle J overlapping each other. The area of Rectangle H is
37 the area of Rectangle J. Given that
13 of Rectangle H is shaded. What fraction of the total area of the figure is unshaded?
Rectangle H |
Rectangle J |
3x1 = 3 u |
7x1 = 7 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
2x1 |
1x1 |
|
1 u |
2 u |
1 u |
6 u |
Rectangle H and Rectangle J share the same shaded area.
Rectangle H is the combined repeated identity. Make the area of Rectangle H the same. LCM of 3 and 3 is 3.
Total unshaded areas
= 2 u + 6 u
= 8 u
Total area of the figure
= 1 u + 2 u + 6 u
= 9 u
Fraction of the figure unshaded
=
89 Answer(s):
89