The figure, not drawn to scale, is made up of Rectangle J and Rectangle K overlapping each other. The area of Rectangle J is
12 the area of Rectangle K. Given that
15 of Rectangle J is shaded. What fraction of the total area of the figure is unshaded?
Rectangle J |
Rectangle K |
1x5 = 5 u |
2x5 = 10 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
4x1 |
1x1 |
|
1 u |
4 u |
1 u |
9 u |
Rectangle J and Rectangle K share the same shaded area.
Rectangle J is the combined repeated identity. Make the area of Rectangle J the same. LCM of 1 and 5 is 5.
Total unshaded areas
= 4 u + 9 u
= 13 u
Total area of the figure
= 1 u + 4 u + 9 u
= 14 u
Fraction of the figure unshaded
=
1314 Answer(s):
1314