The figure, not drawn to scale, is made up of Rectangle L and Rectangle M overlapping each other. The area of Rectangle L is
35 the area of Rectangle M. Given that
14 of Rectangle L is shaded. What fraction of the total area of the figure is unshaded?
| Rectangle L |
Rectangle M |
| 3x4 = 12 u |
5x4 = 20 u |
| Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
| 1x3 |
3x3 |
1x3 |
|
| 3 u |
9 u |
3 u |
17 u |
Rectangle L and Rectangle M share the same shaded area.
Rectangle L is the combined repeated identity. Make the area of Rectangle L the same. LCM of 3 and 4 is 12.
Total unshaded areas
= 9 u + 17 u
= 26 u
Total area of the figure
= 3 u + 9 u + 17 u
= 29 u
Fraction of the figure unshaded
=
2629 Answer(s):
2629 
