The figure, not drawn to scale, is made up of Rectangle S and Rectangle T overlapping each other. The area of Rectangle S is
14 the area of Rectangle T. Given that
15 of Rectangle S is shaded. What fraction of the total area of the figure is unshaded?
Rectangle S |
Rectangle T |
1x5 = 5 u |
4x5 = 20 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
4x1 |
1x1 |
|
1 u |
4 u |
1 u |
19 u |
Rectangle S and Rectangle T share the same shaded area.
Rectangle S is the combined repeated identity. Make the area of Rectangle S the same. LCM of 1 and 5 is 5.
Total unshaded areas
= 4 u + 19 u
= 23 u
Total area of the figure
= 1 u + 4 u + 19 u
= 24 u
Fraction of the figure unshaded
=
2324 Answer(s):
2324