The figure, not drawn to scale, is made up of Rectangle H and Rectangle J overlapping each other. The area of Rectangle H is
37 the area of Rectangle J. Given that
16 of Rectangle H is shaded. What fraction of the total area of the figure is unshaded?
| Rectangle H |
Rectangle J |
| 3x2 = 6 u |
7x2 = 14 u |
| Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
| 1x1 |
5x1 |
1x1 |
|
| 1 u |
5 u |
1 u |
13 u |
Rectangle H and Rectangle J share the same shaded area.
Rectangle H is the combined repeated identity. Make the area of Rectangle H the same. LCM of 3 and 6 is 6.
Total unshaded areas
= 5 u + 13 u
= 18 u
Total area of the figure
= 1 u + 5 u + 13 u
= 19 u
Fraction of the figure unshaded
=
1819 Answer(s):
1819 
