The figure, not drawn to scale, is made up of Rectangle R and Rectangle S overlapping each other. The area of Rectangle R is
12 the area of Rectangle S. Given that
16 of Rectangle R is shaded. What fraction of the total area of the figure is unshaded?
Rectangle R |
Rectangle S |
1x6 = 6 u |
2x6 = 12 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
5x1 |
1x1 |
|
1 u |
5 u |
1 u |
11 u |
Rectangle R and Rectangle S share the same shaded area.
Rectangle R is the combined repeated identity. Make the area of Rectangle R the same. LCM of 1 and 6 is 6.
Total unshaded areas
= 5 u + 11 u
= 16 u
Total area of the figure
= 1 u + 5 u + 11 u
= 17 u
Fraction of the figure unshaded
=
1617 Answer(s):
1617