The figure, not drawn to scale, is made up of Rectangle H and Rectangle J overlapping each other. The area of Rectangle H is
58 the area of Rectangle J. Given that
15 of Rectangle H is shaded. What fraction of the total area of the figure is unshaded?
Rectangle H |
Rectangle J |
5x1 = 5 u |
8x1 = 8 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
4x1 |
1x1 |
|
1 u |
4 u |
1 u |
7 u |
Rectangle H and Rectangle J share the same shaded area.
Rectangle H is the combined repeated identity. Make the area of Rectangle H the same. LCM of 5 and 5 is 5.
Total unshaded areas
= 4 u + 7 u
= 11 u
Total area of the figure
= 1 u + 4 u + 7 u
= 12 u
Fraction of the figure unshaded
=
1112 Answer(s):
1112