The figure, not drawn to scale, is made up of Rectangle M and Rectangle N overlapping each other. The area of Rectangle M is
37 the area of Rectangle N. Given that
12 of Rectangle M is shaded. What fraction of the total area of the figure is unshaded?
Rectangle M |
Rectangle N |
3x2 = 6 u |
7x2 = 14 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x3 |
1x3 |
1x3 |
|
3 u |
3 u |
3 u |
11 u |
Rectangle M and Rectangle N share the same shaded area.
Rectangle M is the combined repeated identity. Make the area of Rectangle M the same. LCM of 3 and 2 is 6.
Total unshaded areas
= 3 u + 11 u
= 14 u
Total area of the figure
= 3 u + 3 u + 11 u
= 17 u
Fraction of the figure unshaded
=
1417 Answer(s):
1417