The figure, not drawn to scale, is made up of Rectangle U and Rectangle V overlapping each other. The area of Rectangle U is
14 the area of Rectangle V. Given that
12 of Rectangle U is shaded. What fraction of the total area of the figure is unshaded?
Rectangle U |
Rectangle V |
1x2 = 2 u |
4x2 = 8 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
1x1 |
1x1 |
|
1 u |
1 u |
1 u |
7 u |
Rectangle U and Rectangle V share the same shaded area.
Rectangle U is the combined repeated identity. Make the area of Rectangle U the same. LCM of 1 and 2 is 2.
Total unshaded areas
= 1 u + 7 u
= 8 u
Total area of the figure
= 1 u + 1 u + 7 u
= 9 u
Fraction of the figure unshaded
=
89 Answer(s):
89