The figure, not drawn to scale, is made up of Rectangle R and Rectangle S overlapping each other. The area of Rectangle R is
38 the area of Rectangle S. Given that
12 of Rectangle R is shaded. What fraction of the total area of the figure is unshaded?
Rectangle R |
Rectangle S |
3x2 = 6 u |
8x2 = 16 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x3 |
1x3 |
1x3 |
|
3 u |
3 u |
3 u |
13 u |
Rectangle R and Rectangle S share the same shaded area.
Rectangle R is the combined repeated identity. Make the area of Rectangle R the same. LCM of 3 and 2 is 6.
Total unshaded areas
= 3 u + 13 u
= 16 u
Total area of the figure
= 3 u + 3 u + 13 u
= 19 u
Fraction of the figure unshaded
=
1619 Answer(s):
1619