The figure, not drawn to scale, is made up of Rectangle D and Rectangle E overlapping each other. The area of Rectangle D is
57 the area of Rectangle E. Given that
12 of Rectangle D is shaded. What fraction of the total area of the figure is unshaded?
Rectangle D |
Rectangle E |
5x2 = 10 u |
7x2 = 14 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x5 |
1x5 |
1x5 |
|
5 u |
5 u |
5 u |
9 u |
Rectangle D and Rectangle E share the same shaded area.
Rectangle D is the combined repeated identity. Make the area of Rectangle D the same. LCM of 5 and 2 is 10.
Total unshaded areas
= 5 u + 9 u
= 14 u
Total area of the figure
= 5 u + 5 u + 9 u
= 19 u
Fraction of the figure unshaded
=
1419 Answer(s):
1419