The figure, not drawn to scale, is made up of Rectangle D and Rectangle E overlapping each other. The area of Rectangle D is
14 the area of Rectangle E. Given that
12 of Rectangle D is shaded. What fraction of the total area of the figure is unshaded?
Rectangle D |
Rectangle E |
1x2 = 2 u |
4x2 = 8 u |
Shaded area |
Unshaded area |
Shaded area |
Unshaded area |
1x1 |
1x1 |
1x1 |
|
1 u |
1 u |
1 u |
7 u |
Rectangle D and Rectangle E share the same shaded area.
Rectangle D is the combined repeated identity. Make the area of Rectangle D the same. LCM of 1 and 2 is 2.
Total unshaded areas
= 1 u + 7 u
= 8 u
Total area of the figure
= 1 u + 1 u + 7 u
= 9 u
Fraction of the figure unshaded
=
89 Answer(s):
89