Hazel, Natalie and Kathy each had some beads and decided to play a game with their beads. In round 1, Hazel lost
12 of her beads to Natalie. In round 2, Natalie lost
12 of her total number of beads to Kathy. In round 3, Kathy lost
12 of her total number of beads to Hazel. In the end, Hazel, Natalie and Kathy had 125, 84 and 60 beads respectively. How many beads did Natalie have at first?
|
Hazel |
Natalie |
Kathy |
Before 1 |
2 b |
103 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
168 |
|
Before 2 |
65 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
120 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Hazel, Natalie and Kathy in the end |
125 |
84 |
60 |
Working backwards.
1 p = 60
At the start of Round 3:
Number of beads that Kathy had
= 2 p
= 2 x 60
= 120
At the start of Round 2:
Number of beads that Hazel had
= 125 - 1 p
= 125 - 60
= 65
At the end of Round 3:
Number of beads that Natalie had = 84
1 u = 84
At the end of Round 1:
Number of beads that Natalie had
= 2 u
= 2 x 84
= 168
1 b = 65
At the end of Round 1:
Number of beads that Hazel had = 65
At the start of Round 1:
Number of beads that Natalie had
= 168 - 1 b
= 168 - 65
= 103
Answer(s): 103