Dana, Lynn and Hazel each had some marbles and decided to play a game with their marbles. In round 1, Dana lost
12 of her marbles to Lynn. In round 2, Lynn lost
12 of her total number of marbles to Hazel. In round 3, Hazel lost
12 of her total number of marbles to Dana. In the end, Dana, Lynn and Hazel had 119, 96 and 54 marbles respectively. How many marbles did Lynn have at first?
|
Dana |
Lynn |
Hazel |
Before 1 |
2 b |
127 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
192 |
|
Before 2 |
65 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
108 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Dana, Lynn and Hazel in the end |
119 |
96 |
54 |
Working backwards.
1 p = 54
At the start of Round 3:
Number of marbles that Hazel had
= 2 p
= 2 x 54
= 108
At the start of Round 2:
Number of marbles that Dana had
= 119 - 1 p
= 119 - 54
= 65
At the end of Round 3:
Number of marbles that Lynn had = 96
1 u = 96
At the end of Round 1:
Number of marbles that Lynn had
= 2 u
= 2 x 96
= 192
1 b = 65
At the end of Round 1:
Number of marbles that Dana had = 65
At the start of Round 1:
Number of marbles that Lynn had
= 192 - 1 b
= 192 - 65
= 127
Answer(s): 127