Yen, Tammy and Fiona each had some marbles and decided to play a game with their marbles. In round 1, Yen lost
12 of her marbles to Tammy. In round 2, Tammy lost
12 of her total number of marbles to Fiona. In round 3, Fiona lost
12 of her total number of marbles to Yen. In the end, Yen, Tammy and Fiona had 120, 92 and 67 marbles respectively. How many marbles did Tammy have at first?
|
Yen |
Tammy |
Fiona |
Before 1 |
2 b |
131 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
184 |
|
Before 2 |
53 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
134 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Yen, Tammy and Fiona in the end |
120 |
92 |
67 |
Working backwards.
1 p = 67
At the start of Round 3:
Number of marbles that Fiona had
= 2 p
= 2 x 67
= 134
At the start of Round 2:
Number of marbles that Yen had
= 120 - 1 p
= 120 - 67
= 53
At the end of Round 3:
Number of marbles that Tammy had = 92
1 u = 92
At the end of Round 1:
Number of marbles that Tammy had
= 2 u
= 2 x 92
= 184
1 b = 53
At the end of Round 1:
Number of marbles that Yen had = 53
At the start of Round 1:
Number of marbles that Tammy had
= 184 - 1 b
= 184 - 53
= 131
Answer(s): 131