Irene, Elyse and Lucy each had some marbles and decided to play a game with their marbles. In round 1, Irene lost
13 of her marbles to Elyse. In round 2, Elyse lost
13 of her total number of marbles to Lucy. In round 3, Lucy lost
13 of her total number of marbles to Irene. In the end, Irene, Elyse and Lucy had 137, 76 and 62 marbles respectively. How many marbles did Elyse have at first?
|
Irene |
Elyse |
Lucy |
|
|
61 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
114 |
|
Before 2 |
106 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
93 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Irene, Elyse and Lucy in the end |
137 |
76 |
62 |
Working backwards.
2 p = 62
1 p = 62 ÷ 2 = 31
At the start of Round 3:
Number of marbles that Lucy had
= 3 p
= 3 x 31
= 93
2 u = 76
1 u = 76 ÷ 2 = 38
At the start of Round 2:
Number of marbles that Elyse had
= 3 u
= 3 x 38
= 114
At the start of Round 2:
Number of marbles that Irene had
= 137 - 31
= 106
2 b = 106
1 b = 106 ÷ 2 = 53
At the start of Round 1:
Number of marbles that Elyse had
= 114 - 1 b
= 114 - 53
= 61
Answer(s): 61