Kathy, Cathy and Gwen each had some balls and decided to play a game with their balls. In round 1, Kathy lost
12 of her balls to Cathy. In round 2, Cathy lost
12 of her total number of balls to Gwen. In round 3, Gwen lost
12 of her total number of balls to Kathy. In the end, Kathy, Cathy and Gwen had 115, 100 and 52 balls respectively. How many balls did Cathy have at first?
|
Kathy |
Cathy |
Gwen |
Before 1 |
2 b |
137 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
200 |
|
Before 2 |
63 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
104 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Kathy, Cathy and Gwen in the end |
115 |
100 |
52 |
Working backwards.
1 p = 52
At the start of Round 3:
Number of balls that Gwen had
= 2 p
= 2 x 52
= 104
At the start of Round 2:
Number of balls that Kathy had
= 115 - 1 p
= 115 - 52
= 63
At the end of Round 3:
Number of balls that Cathy had = 100
1 u = 100
At the end of Round 1:
Number of balls that Cathy had
= 2 u
= 2 x 100
= 200
1 b = 63
At the end of Round 1:
Number of balls that Kathy had = 63
At the start of Round 1:
Number of balls that Cathy had
= 200 - 1 b
= 200 - 63
= 137
Answer(s): 137