Shiyun, Jane and Sabrina each had some beads and decided to play a game with their beads. In round 1, Shiyun lost
12 of her beads to Jane. In round 2, Jane lost
12 of her total number of beads to Sabrina. In round 3, Sabrina lost
12 of her total number of beads to Shiyun. In the end, Shiyun, Jane and Sabrina had 140, 88 and 71 beads respectively. How many beads did Jane have at first?
|
Shiyun |
Jane |
Sabrina |
Before 1 |
2 b |
107 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
176 |
|
Before 2 |
69 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
142 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Shiyun, Jane and Sabrina in the end |
140 |
88 |
71 |
Working backwards.
1 p = 71
At the start of Round 3:
Number of beads that Sabrina had
= 2 p
= 2 x 71
= 142
At the start of Round 2:
Number of beads that Shiyun had
= 140 - 1 p
= 140 - 71
= 69
At the end of Round 3:
Number of beads that Jane had = 88
1 u = 88
At the end of Round 1:
Number of beads that Jane had
= 2 u
= 2 x 88
= 176
1 b = 69
At the end of Round 1:
Number of beads that Shiyun had = 69
At the start of Round 1:
Number of beads that Jane had
= 176 - 1 b
= 176 - 69
= 107
Answer(s): 107