Zoe, Irene and Sabrina each had some beads and decided to play a game with their beads. In round 1, Zoe lost
12 of her beads to Irene. In round 2, Irene lost
12 of her total number of beads to Sabrina. In round 3, Sabrina lost
12 of her total number of beads to Zoe. In the end, Zoe, Irene and Sabrina had 111, 87 and 69 beads respectively. How many beads did Irene have at first?
|
Zoe |
Irene |
Sabrina |
Before 1 |
2 b |
132 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
174 |
|
Before 2 |
42 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
138 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Zoe, Irene and Sabrina in the end |
111 |
87 |
69 |
Working backwards.
1 p = 69
At the start of Round 3:
Number of beads that Sabrina had
= 2 p
= 2 x 69
= 138
At the start of Round 2:
Number of beads that Zoe had
= 111 - 1 p
= 111 - 69
= 42
At the end of Round 3:
Number of beads that Irene had = 87
1 u = 87
At the end of Round 1:
Number of beads that Irene had
= 2 u
= 2 x 87
= 174
1 b = 42
At the end of Round 1:
Number of beads that Zoe had = 42
At the start of Round 1:
Number of beads that Irene had
= 174 - 1 b
= 174 - 42
= 132
Answer(s): 132