Natalie, Tiffany and Eva each had some marbles and decided to play a game with their marbles. In round 1, Natalie lost
12 of her marbles to Tiffany. In round 2, Tiffany lost
12 of her total number of marbles to Eva. In round 3, Eva lost
12 of her total number of marbles to Natalie. In the end, Natalie, Tiffany and Eva had 114, 94 and 62 marbles respectively. How many marbles did Tiffany have at first?
|
Natalie |
Tiffany |
Eva |
Before 1 |
2 b |
136 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
188 |
|
Before 2 |
52 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
124 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Natalie, Tiffany and Eva in the end |
114 |
94 |
62 |
Working backwards.
1 p = 62
At the start of Round 3:
Number of marbles that Eva had
= 2 p
= 2 x 62
= 124
At the start of Round 2:
Number of marbles that Natalie had
= 114 - 1 p
= 114 - 62
= 52
At the end of Round 3:
Number of marbles that Tiffany had = 94
1 u = 94
At the end of Round 1:
Number of marbles that Tiffany had
= 2 u
= 2 x 94
= 188
1 b = 52
At the end of Round 1:
Number of marbles that Natalie had = 52
At the start of Round 1:
Number of marbles that Tiffany had
= 188 - 1 b
= 188 - 52
= 136
Answer(s): 136