Olivia, Opal and Jean each had some marbles and decided to play a game with their marbles. In round 1, Olivia lost
12 of her marbles to Opal. In round 2, Opal lost
12 of her total number of marbles to Jean. In round 3, Jean lost
12 of her total number of marbles to Olivia. In the end, Olivia, Opal and Jean had 125, 86 and 71 marbles respectively. How many marbles did Opal have at first?
|
Olivia |
Opal |
Jean |
Before 1 |
2 b |
118 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
172 |
|
Before 2 |
54 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
142 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Olivia, Opal and Jean in the end |
125 |
86 |
71 |
Working backwards.
1 p = 71
At the start of Round 3:
Number of marbles that Jean had
= 2 p
= 2 x 71
= 142
At the start of Round 2:
Number of marbles that Olivia had
= 125 - 1 p
= 125 - 71
= 54
At the end of Round 3:
Number of marbles that Opal had = 86
1 u = 86
At the end of Round 1:
Number of marbles that Opal had
= 2 u
= 2 x 86
= 172
1 b = 54
At the end of Round 1:
Number of marbles that Olivia had = 54
At the start of Round 1:
Number of marbles that Opal had
= 172 - 1 b
= 172 - 54
= 118
Answer(s): 118