Ivory, Roshel and Tina each had some beads and decided to play a game with their beads. In round 1, Ivory lost
13 of her beads to Roshel. In round 2, Roshel lost
13 of her total number of beads to Tina. In round 3, Tina lost
13 of her total number of beads to Ivory. In the end, Ivory, Roshel and Tina had 139, 90 and 62 beads respectively. How many beads did Roshel have at first?
|
Ivory |
Roshel |
Tina |
|
|
81 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
135 |
|
Before 2 |
108 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
93 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Ivory, Roshel and Tina in the end |
139 |
90 |
62 |
Working backwards.
2 p = 62
1 p = 62 ÷ 2 = 31
At the start of Round 3:
Number of beads that Tina had
= 3 p
= 3 x 31
= 93
2 u = 90
1 u = 90 ÷ 2 = 45
At the start of Round 2:
Number of beads that Roshel had
= 3 u
= 3 x 45
= 135
At the start of Round 2:
Number of beads that Ivory had
= 139 - 31
= 108
2 b = 108
1 b = 108 ÷ 2 = 54
At the start of Round 1:
Number of beads that Roshel had
= 135 - 1 b
= 135 - 54
= 81
Answer(s): 81