Cathy, Gillian and Jane each had some marbles and decided to play a game with their marbles. In round 1, Cathy lost
12 of her marbles to Gillian. In round 2, Gillian lost
12 of her total number of marbles to Jane. In round 3, Jane lost
12 of her total number of marbles to Cathy. In the end, Cathy, Gillian and Jane had 112, 96 and 62 marbles respectively. How many marbles did Gillian have at first?
|
Cathy |
Gillian |
Jane |
Before 1 |
2 b |
142 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
192 |
|
Before 2 |
50 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
124 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Cathy, Gillian and Jane in the end |
112 |
96 |
62 |
Working backwards.
1 p = 62
At the start of Round 3:
Number of marbles that Jane had
= 2 p
= 2 x 62
= 124
At the start of Round 2:
Number of marbles that Cathy had
= 112 - 1 p
= 112 - 62
= 50
At the end of Round 3:
Number of marbles that Gillian had = 96
1 u = 96
At the end of Round 1:
Number of marbles that Gillian had
= 2 u
= 2 x 96
= 192
1 b = 50
At the end of Round 1:
Number of marbles that Cathy had = 50
At the start of Round 1:
Number of marbles that Gillian had
= 192 - 1 b
= 192 - 50
= 142
Answer(s): 142