Usha, Irene and Nicole each had some marbles and decided to play a game with their marbles. In round 1, Usha lost
12 of her marbles to Irene. In round 2, Irene lost
12 of her total number of marbles to Nicole. In round 3, Nicole lost
12 of her total number of marbles to Usha. In the end, Usha, Irene and Nicole had 114, 81 and 54 marbles respectively. How many marbles did Irene have at first?
|
Usha |
Irene |
Nicole |
Before 1 |
2 b |
102 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
162 |
|
Before 2 |
60 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
108 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Usha, Irene and Nicole in the end |
114 |
81 |
54 |
Working backwards.
1 p = 54
At the start of Round 3:
Number of marbles that Nicole had
= 2 p
= 2 x 54
= 108
At the start of Round 2:
Number of marbles that Usha had
= 114 - 1 p
= 114 - 54
= 60
At the end of Round 3:
Number of marbles that Irene had = 81
1 u = 81
At the end of Round 1:
Number of marbles that Irene had
= 2 u
= 2 x 81
= 162
1 b = 60
At the end of Round 1:
Number of marbles that Usha had = 60
At the start of Round 1:
Number of marbles that Irene had
= 162 - 1 b
= 162 - 60
= 102
Answer(s): 102