Shiyun, Raeann and Jean each had some marbles and decided to play a game with their marbles. In round 1, Shiyun lost
13 of her marbles to Raeann. In round 2, Raeann lost
13 of her total number of marbles to Jean. In round 3, Jean lost
13 of her total number of marbles to Shiyun. In the end, Shiyun, Raeann and Jean had 124, 94 and 56 marbles respectively. How many marbles did Raeann have at first?
|
Shiyun |
Raeann |
Jean |
|
|
93 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
141 |
|
Before 2 |
96 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
84 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Shiyun, Raeann and Jean in the end |
124 |
94 |
56 |
Working backwards.
2 p = 56
1 p = 56 ÷ 2 = 28
At the start of Round 3:
Number of marbles that Jean had
= 3 p
= 3 x 28
= 84
2 u = 94
1 u = 94 ÷ 2 = 47
At the start of Round 2:
Number of marbles that Raeann had
= 3 u
= 3 x 47
= 141
At the start of Round 2:
Number of marbles that Shiyun had
= 124 - 28
= 96
2 b = 96
1 b = 96 ÷ 2 = 48
At the start of Round 1:
Number of marbles that Raeann had
= 141 - 1 b
= 141 - 48
= 93
Answer(s): 93