Hazel, Dana and Yen each had some marbles and decided to play a game with their marbles. In round 1, Hazel lost
12 of her marbles to Dana. In round 2, Dana lost
12 of her total number of marbles to Yen. In round 3, Yen lost
12 of her total number of marbles to Hazel. In the end, Hazel, Dana and Yen had 111, 87 and 57 marbles respectively. How many marbles did Dana have at first?
|
Hazel |
Dana |
Yen |
Before 1 |
2 b |
120 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
174 |
|
Before 2 |
54 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
114 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Hazel, Dana and Yen in the end |
111 |
87 |
57 |
Working backwards.
1 p = 57
At the start of Round 3:
Number of marbles that Yen had
= 2 p
= 2 x 57
= 114
At the start of Round 2:
Number of marbles that Hazel had
= 111 - 1 p
= 111 - 57
= 54
At the end of Round 3:
Number of marbles that Dana had = 87
1 u = 87
At the end of Round 1:
Number of marbles that Dana had
= 2 u
= 2 x 87
= 174
1 b = 54
At the end of Round 1:
Number of marbles that Hazel had = 54
At the start of Round 1:
Number of marbles that Dana had
= 174 - 1 b
= 174 - 54
= 120
Answer(s): 120