Jade, Vanessa and Victoria each had some beads and decided to play a game with their beads. In round 1, Jade lost
13 of her beads to Vanessa. In round 2, Vanessa lost
13 of her total number of beads to Victoria. In round 3, Victoria lost
13 of her total number of beads to Jade. In the end, Jade, Vanessa and Victoria had 143, 74 and 66 beads respectively. How many beads did Vanessa have at first?
|
Jade |
Vanessa |
Victoria |
|
|
56 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
111 |
|
Before 2 |
110 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
99 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Jade, Vanessa and Victoria in the end |
143 |
74 |
66 |
Working backwards.
2 p = 66
1 p = 66 ÷ 2 = 33
At the start of Round 3:
Number of beads that Victoria had
= 3 p
= 3 x 33
= 99
2 u = 74
1 u = 74 ÷ 2 = 37
At the start of Round 2:
Number of beads that Vanessa had
= 3 u
= 3 x 37
= 111
At the start of Round 2:
Number of beads that Jade had
= 143 - 33
= 110
2 b = 110
1 b = 110 ÷ 2 = 55
At the start of Round 1:
Number of beads that Vanessa had
= 111 - 1 b
= 111 - 55
= 56
Answer(s): 56