Cathy, Olivia and Joelle each had some balls and decided to play a game with their balls. In round 1, Cathy lost
12 of her balls to Olivia. In round 2, Olivia lost
12 of her total number of balls to Joelle. In round 3, Joelle lost
12 of her total number of balls to Cathy. In the end, Cathy, Olivia and Joelle had 125, 81 and 69 balls respectively. How many balls did Olivia have at first?
|
Cathy |
Olivia |
Joelle |
Before 1 |
2 b |
106 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
162 |
|
Before 2 |
56 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
138 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Cathy, Olivia and Joelle in the end |
125 |
81 |
69 |
Working backwards.
1 p = 69
At the start of Round 3:
Number of balls that Joelle had
= 2 p
= 2 x 69
= 138
At the start of Round 2:
Number of balls that Cathy had
= 125 - 1 p
= 125 - 69
= 56
At the end of Round 3:
Number of balls that Olivia had = 81
1 u = 81
At the end of Round 1:
Number of balls that Olivia had
= 2 u
= 2 x 81
= 162
1 b = 56
At the end of Round 1:
Number of balls that Cathy had = 56
At the start of Round 1:
Number of balls that Olivia had
= 162 - 1 b
= 162 - 56
= 106
Answer(s): 106