Gillian, Nicole and Kimberly each had some beads and decided to play a game with their beads. In round 1, Gillian lost
12 of her beads to Nicole. In round 2, Nicole lost
12 of her total number of beads to Kimberly. In round 3, Kimberly lost
12 of her total number of beads to Gillian. In the end, Gillian, Nicole and Kimberly had 119, 99 and 52 beads respectively. How many beads did Nicole have at first?
|
Gillian |
Nicole |
Kimberly |
Before 1 |
2 b |
131 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
198 |
|
Before 2 |
67 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
104 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Gillian, Nicole and Kimberly in the end |
119 |
99 |
52 |
Working backwards.
1 p = 52
At the start of Round 3:
Number of beads that Kimberly had
= 2 p
= 2 x 52
= 104
At the start of Round 2:
Number of beads that Gillian had
= 119 - 1 p
= 119 - 52
= 67
At the end of Round 3:
Number of beads that Nicole had = 99
1 u = 99
At the end of Round 1:
Number of beads that Nicole had
= 2 u
= 2 x 99
= 198
1 b = 67
At the end of Round 1:
Number of beads that Gillian had = 67
At the start of Round 1:
Number of beads that Nicole had
= 198 - 1 b
= 198 - 67
= 131
Answer(s): 131