Opal, Emma and Gwen each had some balls and decided to play a game with their balls. In round 1, Opal lost
13 of her balls to Emma. In round 2, Emma lost
13 of her total number of balls to Gwen. In round 3, Gwen lost
13 of her total number of balls to Opal. In the end, Opal, Emma and Gwen had 119, 90 and 50 balls respectively. How many balls did Emma have at first?
|
Opal |
Emma |
Gwen |
|
|
88 |
|
Before 1 |
3 b |
|
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
2 b |
135 |
|
Before 2 |
94 |
3 u |
|
Change 2 |
|
- 1 u |
+ 1 u |
After 2 |
|
2 u |
75 |
Before 3 |
|
|
3 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
2 p |
Comparing Opal, Emma and Gwen in the end |
119 |
90 |
50 |
Working backwards.
2 p = 50
1 p = 50 ÷ 2 = 25
At the start of Round 3:
Number of balls that Gwen had
= 3 p
= 3 x 25
= 75
2 u = 90
1 u = 90 ÷ 2 = 45
At the start of Round 2:
Number of balls that Emma had
= 3 u
= 3 x 45
= 135
At the start of Round 2:
Number of balls that Opal had
= 119 - 25
= 94
2 b = 94
1 b = 94 ÷ 2 = 47
At the start of Round 1:
Number of balls that Emma had
= 135 - 1 b
= 135 - 47
= 88
Answer(s): 88