Yen, Sarah and Emily each had some balls and decided to play a game with their balls. In round 1, Yen lost
12 of her balls to Sarah. In round 2, Sarah lost
12 of her total number of balls to Emily. In round 3, Emily lost
12 of her total number of balls to Yen. In the end, Yen, Sarah and Emily had 137, 105 and 59 balls respectively. How many balls did Sarah have at first?
|
Yen |
Sarah |
Emily |
Before 1 |
2 b |
132 |
|
Change 1 |
- 1 b |
+ 1 b |
|
After 1 |
1 b |
210 |
|
Before 2 |
78 |
2 u |
|
Change 2 |
|
- 1 u |
+1 |
After 2 |
|
1 u |
118 |
Before 3 |
|
|
2 p |
Change 3 |
+ 1 p |
|
- 1 p |
After 3 |
|
|
1 p |
Comparing Yen, Sarah and Emily in the end |
137 |
105 |
59 |
Working backwards.
1 p = 59
At the start of Round 3:
Number of balls that Emily had
= 2 p
= 2 x 59
= 118
At the start of Round 2:
Number of balls that Yen had
= 137 - 1 p
= 137 - 59
= 78
At the end of Round 3:
Number of balls that Sarah had = 105
1 u = 105
At the end of Round 1:
Number of balls that Sarah had
= 2 u
= 2 x 105
= 210
1 b = 78
At the end of Round 1:
Number of balls that Yen had = 78
At the start of Round 1:
Number of balls that Sarah had
= 210 - 1 b
= 210 - 78
= 132
Answer(s): 132