There were some pears at a stall. In the morning,
14 of pears were sold. In the afternoon, another 30 pears were sold. The total number of pears left was 10 less than
512 of the number of pears the stall had at first.
- How many pears were there at first?
- What fraction of the pears in the stall remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
4x3 =
12 u |
12x1 =
12 u |
| Change 1 |
- 1x3 =
- 3 u |
|
| After 1 |
3x3 =
9 u |
| Change 2 |
- 30 |
After 2 |
9 u - 30 |
5x1 - 10 =
5 u - 10 |
(a)
The number of pears at first is repeated in both comparisons. Make the number of pears at first. LCM of 4 and 12 is 12.
The number of pears in the end is the same in both comparisons.
9 u - 30 = 5 u - 10
9 u - 5 u = 30 - 10
4 u = 20
1 u = 20 ÷ 4 = 5
Number of pears at first
= 12 u
= 12 x 5
= 60
(b)
Number of pears that remained unsold
= 9 u - 30
= 9 x 5 - 30
= 45 - 30
= 15
Fraction of pears that remained unsold
=
1560=
14Answer(s): (a) 60; (b)
14 
