There were some chikoos at a market. In the morning,
14 of chikoos were sold. In the afternoon, another 31 chikoos were sold. The total number of chikoos sold was 8 less than
57 of the number of chikoos the market had at first.
- How many chikoos were there at first?
- What fraction of the chikoos in the market remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
4x7 =
28 u |
7x4 =
28 u |
| Change 1 |
- 1x7 =
- 7 u |
|
| After 1 |
3x7 =
21 u |
| Change 2 |
- 31 |
After 2 |
21 u - 31 |
5x4 - 8 =
20 u - 8 |
(a)
The number of chikoos at first is repeated in both comparisons. Make the number of chikoos at first. LCM of 4 and 7 is 28.
The number of chikoos in the end is the same in both comparisons.
21 u - 31 = 20 u - 8
21 u - 20 u = 31 - 8
13 u = 39
1 u = 39 ÷ 13 = 3
Number of chikoos at first
= 28 u
= 28 x 3
= 84
(b)
Number of chikoos that remained unsold
= 8 u + 8
= 8 x 3 + 8
= 32
Fraction of chikoos that remained unsold
=
3284=
821Answer(s): (a) 84; (b)
821 
