There were some peaches at a supermarket. In the morning,
14 of peaches were sold. In the afternoon, another 40 peaches were sold. The total number of peaches sold was 8 less than
34 of the number of peaches the supermarket had at first.
- How many peaches were there at first?
- What fraction of the peaches in the supermarket remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
4x1 = 4 u |
4x1 = 4 u |
Change 1 |
- 1x1 = - 1 u |
|
After 1 |
3x1 = 3 u |
Change 2 |
- 40 |
After 2 |
3 u - 40 |
3x1 - 8 = 3 u - 8 |
(a)
The number of peaches at first is repeated in both comparisons. Make the number of peaches at first. LCM of 4 and 4 is 4.
The number of peaches in the end is the same in both comparisons.
3 u - 40 = 3 u - 8
3 u - 3 u = 40 - 8
2 u = 48
1 u = 48 ÷ 2 = 24
Number of peaches at first
= 4 u
= 4 x 24
= 96
(b)
Number of peaches that remained unsold
= 1 u + 8
= 1 x 24 + 8
= 32
Fraction of peaches that remained unsold
=
3296=
13Answer(s): (a) 96; (b)
13