There were some peaches at a stall. In the morning,
16 of peaches were sold. In the afternoon, another 26 peaches were sold. The total number of peaches sold was 8 less than
47 of the number of peaches the stall had at first.
- How many peaches were there at first?
- What fraction of the peaches in the stall remained unsold in the afternoon?
| |
Comparison 1 |
Comparison 2 |
| Before |
6x7 =
42 u |
7x6 =
42 u |
| Change 1 |
- 1x7 =
- 7 u |
|
| After 1 |
5x7 =
35 u |
| Change 2 |
- 26 |
After 2 |
35 u - 26 |
4x6 - 8 =
24 u - 8 |
(a)
The number of peaches at first is repeated in both comparisons. Make the number of peaches at first. LCM of 6 and 7 is 42.
The number of peaches in the end is the same in both comparisons.
35 u - 26 = 24 u - 8
35 u - 24 u = 26 - 8
17 u = 34
1 u = 34 ÷ 17 = 2
Number of peaches at first
= 42 u
= 42 x 2
= 84
(b)
Number of peaches that remained unsold
= 18 u + 8
= 18 x 2 + 8
= 44
Fraction of peaches that remained unsold
=
4484=
1121Answer(s): (a) 84; (b)
1121 
