There were some pears at a stall. In the morning,
13 of pears were sold. In the afternoon, another 28 pears were sold. The total number of pears sold was 2 less than
712 of the number of pears the stall had at first.
- How many pears were there at first?
- What fraction of the pears in the stall remained unsold in the afternoon?
|
Comparison 1 |
Comparison 2 |
Before |
3x4 = 12 u |
12x1 = 12 u |
Change 1 |
- 1x4 = - 4 u |
|
After 1 |
2x4 = 8 u |
Change 2 |
- 28 |
After 2 |
8 u - 28 |
7x1 - 2 = 7 u - 2 |
(a)
The number of pears at first is repeated in both comparisons. Make the number of pears at first. LCM of 3 and 12 is 12.
The number of pears in the end is the same in both comparisons.
8 u - 28 = 7 u - 2
8 u - 7 u = 28 - 2
3 u = 30
1 u = 30 ÷ 3 = 10
Number of pears at first
= 12 u
= 12 x 10
= 120
(b)
Number of pears that remained unsold
= 5 u + 2
= 5 x 10 + 2
= 52
Fraction of pears that remained unsold
=
52120=
1330Answer(s): (a) 120; (b)
1330